- Pakistan Cricket Board Announces Playing XI for T20I against Zimbabwe
- Pakistan won the first match by 57 runs, with Abrar Ahmed and Sufyan Moqim claiming three wickets each.
- In the second match, Pakistan won by 58 runs without losing a wicket, with Saim Ayub scoring 36 runs.
The Pakistan Cricket Board (PCB) announced the playing XI for the Green Shirts in the third and final T20I against Zimbabwe, scheduled for Thursday at Queens Sports Club in Bulawayo. Pakistan has already clinched the series 2-0, having won the first match by 57 runs and the second by 10 wickets.
The playing XI, led by Salman Ali Agha, includes Omair bin Yousuf, Sahibzada Farhan, Usman Khan, Tayyab Tahir, Qasim Akram, Arafat Minhas, and Jahandad Khan. The bowling attack features Mohammad Abbas Afridi, Mohammad Hasnain, and Sufyan Moqim.
In the opening T20I, Pakistan triumphed by 57 runs, thanks to outstanding performances from Abrar Ahmed and Sufyan Moqim, both of whom claimed three wickets each. Haris Rauf picked up two wickets, and Jahandad Khan took one. Zimbabwe, chasing a target of 164, was dismissed for 108 in just 15.3 overs, despite solid knocks from skipper Sikandar Raza and opener Tadiwanashe Marumani.
In the second T20I, Pakistan won in dominant fashion, chasing down a modest target of 58 runs without losing a wicket. Saim Ayub played a pivotal role, scoring a quickfire 36 runs from 18 balls, including six fours and a six, to seal the victory during the batting powerplay.
